How do you solve $5/7=(x-2)/4$ ?

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Answer 1 · 2018-05-12T15:36:26

try to get rid of the fractions; Solve equation

multiply on both sides with your denominators (4 and 7)

$5/7 = (x-2)/4$ |*4

$(5*4)/7=(x-2)$ |*7

$(5*4)=(x-2)*7$

$20=7x-14$

solve the equation by moving the x-parts to on side and the normal numbers to the other (always move by using the opposite compute-sign)

$20=7x-14$ |+14

$20+14=7x$

$34=7x$ |:7

$34/7=x$

$x=4 6/7$

How do you solve 5/7=(x-2)/45/7=(x-2)/4?