Solve the equation sin x + sin 2x = 0 , for 0°< x < 360°? Trigonometry 1 Answer James May 10, 2018 show the answer below Explanation: show below sinx+sin2x=0sinx+sin2x=0 sinx+[2*sinx*cosx]=0sinx+[2⋅sinx⋅cosx]=0 sinx[1+2cosx]=0sinx[1+2cosx]=0 sinx=0sinx=0 x=0,x=2pi or x=pix=0,x=2πorx=π 1+2cosx=01+2cosx=0 2cosx=-12cosx=−1 cosx=-1/2cosx=−12 x=(2pi)/3 or x=(4pi)/3x=2π3orx=4π3 note that sin2x=2*sinx*cosxsin2x=2⋅sinx⋅cosx Answer link Related questions How do I determine the molecular shape of a molecule? What is the lewis structure for co2? What is the lewis structure for hcn? How is vsepr used to classify molecules? What are the units used for the ideal gas law? How does Charle's law relate to breathing? What is the ideal gas law constant? How do you calculate the ideal gas law constant? How do you find density in the ideal gas law? Does ideal gas law apply to liquids? Impact of this question 5947 views around the world You can reuse this answer Creative Commons License