I am using V+E-Ir. But I can't get the answer yet as 05 or 0.6 ohm? How?

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1 Answer
1s2s2p
May 10, 2018

#r~~0.59Omega#

Explanation:

The graph plotted follows the equation #V=epsilon-Ir#, which is equivalent to #y=mx+c#

#[(V,=,epsilon,-I,r),(y,=,c,+m,x)]#

So, therefore the gradient is #-r=-(DeltaV)/(DeltaI)~~-(0.30-1.30)/(2.00-0.30)=-1/1.7=-10/17#

#r=-(-10/17)=10/17~~0.59Omega#

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