How do you solve $\frac { 16} { 3} x = \frac { 1} { 2} ( x + \frac { 4} { 5} ) + \frac { 1} { 4}$ ?

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How do you solve $\frac { 16} { 3} x = \frac { 1} { 2} ( x + \frac { 4} { 5} ) + \frac { 1} { 4}$ ?

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Answer 1 · 2018-05-09T18:29:44

$16/3x=1/2(x+4/5)+1/4$
$12*16/3x=12*1/2(x+4/5)+12*1/4$
$4*16x=6*1(x+4/5)+3*1$
$64x=6x+24/5+3$
$64x-6x=24/5+3$
$5*58x=5*24/5+5*3$
$290x=24+15$
$290x=39$
$x=39/290$

Explanation:

Pretty self explanatory.

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How do you solve $\frac { 16} { 3} x = \frac { 1} { 2} ( x + \frac { 4} { 5} ) + \frac { 1} { 4}$ ?

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How do you solve \frac { 16} { 3} x = \frac { 1} { 2} ( x + \frac { 4} { 5} ) + \frac { 1} { 4}\frac { 16} { 3} x = \frac { 1} { 2} ( x + \frac { 4} { 5} ) + \frac { 1} { 4}?

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How do you solve $\frac { 16} { 3} x = \frac { 1} { 2} ( x + \frac { 4} { 5} ) + \frac { 1} { 4}$ ?