What is the area under #f(x)=5# in #x in[0,2] #?

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Answer 1 · 2018-05-07T20:38:54

#10m^2#

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#Area_((OABΓ))=x*y=2*5=10m^2#

or

#int_0^2##5dx# #=# #5int_0^2##(x)'dx# #=#

#5[x]_0^2=5(2-0)=5*2=10m^2#

(Used the greek letter #Γ# for #O(0,0#))