For example, f(x) is a multipart which if divided by x^3+27x3+27, the remainder is x^2-2x+7x22x+7. If f(x) is divided by x^2-3x+9x23x+9, the remainder is?

1 Answer
May 7, 2018

x-2x2

Explanation:

Since x^2-3x+9x23x+9 is a divisor of x^3+27x3+27, we need only find the remainder of (x^2-2x+7) -: (x^2-3x+9)(x22x+7)÷(x23x+9).

That remainder is (x^2-2x+7) - (x^2-3x+9)(x22x+7)(x23x+9), which is x-2x2