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For example, f(x) is a multipart which if divided by #x^3+27#, the remainder is #x^2-2x+7#. If f(x) is divided by #x^2-3x+9#, the remainder is?

1 Answer

May 7, 2018

#x-2#

Explanation:

Since #x^2-3x+9# is a divisor of #x^3+27#, we need only find the remainder of #(x^2-2x+7) -: (x^2-3x+9)#.

That remainder is #(x^2-2x+7) - (x^2-3x+9)#, which is #x-2#

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