How do you express the complex number in trigonometric form #2(cos 180° + i sin 180°)#?

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How do you express the complex number in trigonometric form #2(cos 180° + i sin 180°)#?

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Answer 1 · 2018-05-07T01:58:15

The complex number is already in trigonometric form

Explanation:

The trigonometric form of a complex number #a+bi# is #r(costheta+isintheta)# where #r=sqrt(a^2+b^2)# and #theta# satisfies #theta=arccosa"/"r,theta=arcsin b"/"r#

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How do you express the complex number in trigonometric form #2(cos 180° + i sin 180°)#?

1 Answer

Explanation:

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