How do you factor -3x^2+2x+2?

2 Answers
May 5, 2018

-(3x^2-2x-2)(3x22x2)

Explanation:

-3x^2+2x+23x2+2x+2

Factor the negative out,

-(3x^2-2x-2)(3x22x2)

May 5, 2018

(x+(1-sqrt7)/3)(x+(1+sqrt7)/3)(x+173)(x+1+73)

Explanation:

-3x^2+2x+23x2+2x+2

Using the quadratic formula given by:

x=(-b+-sqrt(b^2-4ac))/(2a)x=b±b24ac2a

Since the equation is in the general form ax^2+bx+cax2+bx+c where a=-3a=3, b=2b=2 and c=2c=2

x=(-2+-sqrt(4+24))/(-6x=2±4+246

x=(-2+-sqrt28)/-6x=2±286

x=(-2+-2sqrt7)/-6x=2±276

x=(-1+-sqrt7)/-3x=1±73

Therefore,

(x-((-1+sqrt7)/-3))(x-((-1-sqrt7)/-3))(x(1+73))(x(173))

= (x-(-1)(1-sqrt7)/3)(x-(-1)(1+sqrt7)/3)(x(1)173)(x(1)1+73)

= (x+(1-sqrt7)/3)(x+(1+sqrt7)/3)(x+173)(x+1+73)