How do you solve #4( c + 1) + 2c + 3( c - 1) = 37#?

Question

How do you solve #4( c + 1) + 2c + 3( c - 1) = 37#?

1 Answer

Impact of this question

1120 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-05T10:28:28

#c=4#

Explanation:

Expand all the terms first
#4c+4+2c+3c-3=37#
Then shift all the numbers to the left
#4c+2c+3c=37+3-4#
#9c=36#
Then divide both sides by 9
#(9c)/9=36/9#
#c=4#

Science

Math

Humanities

... and beyond

How do you solve #4( c + 1) + 2c + 3( c - 1) = 37#?

1 Answer

Explanation:

Related questions

Impact of this question