How do you solve #4( c + 1) + 2c + 3( c - 1) = 37#?

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How do you solve #4( c + 1) + 2c + 3( c - 1) = 37#?

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Answer 1 · 2018-05-05T10:28:28

#c=4#

Explanation:

Expand all the terms first
#4c+4+2c+3c-3=37#
Then shift all the numbers to the left
#4c+2c+3c=37+3-4#
#9c=36#
Then divide both sides by 9
#(9c)/9=36/9#
#c=4#

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How do you solve #4( c + 1) + 2c + 3( c - 1) = 37#?

1 Answer

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