How do you find the product of #(y + 8) (y + 6) #?

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Answer 1 · 2018-05-03T15:44:48

#y^2 + 14x +48#

To multiply the binomials #(y+8)(y+6)#
we would incorporate the FOIL

F = Firsts
O = Outers
I = Inners
L = Lasts

Multiplying the Firsts #y*y#
Multiplying the Outers #+6*y# and #+8*y#
Multiplying the Lasts #(+8)*(+6)#

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We get
#y^2 + 6y + 8y + 48#

Now add like terms

#y^2 +14x + 48#