What is the derivative for y=tan(x)+x^(5/2)+2x?

1 Answer
May 2, 2018

dy/dx=sec^2x+5/2x^(3/2)+2

Explanation:

y=tanx+x^(5/2)+2x

color(green)(d/dxtanu=sec^2ucolor(blue)((du)/dxcolor(red)(rarr"Where u is a function of " x

color(green)(d/dxu^n=n*u^(n-1)color(blue)((du)/dxcolor(red)(rarr"Where u is a function of " x

dy/dx=color(green)(sec^2x)color(blue)(xx1)+color(green)(5/2x^(3/2))color(blue)(xx1)+color(green)(2color(blue)(xx1)

=sec^2x+5/2x^(3/2)+2

For additional information about the rules I used you can check those links: