How do you factor the expression # 81x^(4/5) - 256#? Algebra Polynomials and Factoring Factoring Completely 1 Answer Yahia M. May 2, 2018 #(9x^(2/5)-16)*(9x^(2/5)+16)# Explanation: Difference Between Two Squared Numbers #(sqrt(81x^(4/5))-sqrt(256))*(sqrt(81x^(4/5))+sqrt(256))# #color(green)(sqrt(81x^(4/5))=9x^(2/5)# #color(green)(sqrt(256)=16# #(9x^(2/5)-16)*(9x^(2/5)+16)# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 1535 views around the world You can reuse this answer Creative Commons License