What is the phase shift for the function: #f( x ) = \sin ( 2x - \frac { \pi } { 3} ) + \frac { \pi } { 2}#?

1 Answer
MAXIMILIAN C.
May 2, 2018

#pi/6#

Explanation:

First, get the equation into the form:
#y=asinb(x-c)+d#. This requires factoring out #x#'s coefficeintL
#y=sin2(2/2x-pi/(3*2))+pi/2# Simplify:
#y=sin2(x-pi/6)+pi/2#

Since the phase shift is #-c#, and the #c# term is #-pi/6#, the phase shift is #pi/6#.

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