How do you find the $y$ $y$ -intercept of $- 8 x + 6 y = 42$ $-8x + 6y = 42$ ?

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Answer 1 · 2018-05-02T02:25:54

The $y$ $y$ intercept is at $(0, 7)$ $(0,7)$ .

When you have a linear equation in the form $a x + b x = c$ $ax+bx=c$ , just substitute $0$ $0$ in the place of $x$ $x$ to get the $y$ $y$ intercept.

$\Rightarrow (- 8) (0) + 6 y = 42$ $=>(-8)(0)+6y=42$ solve for $y$ $y$ .

$\Rightarrow 0 + 6 y = 42$ $=>0+6y=42$

$\Rightarrow 6 y = 42$ $=>6y=42$

$\Rightarrow y = 7$ $=>y=7$ The $y$ $y$ -intercept is at $(0, 7)$ $(0,7)$

How do you find the yy-intercept of −8x+6y=42-8x + 6y = 42?