How do you find the $y$ -intercept of $-8x + 6y = 42$ ?

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Answer 1 · 2018-05-02T02:25:54

The $y$ intercept is at $(0,7)$ .

When you have a linear equation in the form $ax+bx=c$ , just substitute $0$ in the place of $x$ to get the $y$ intercept.

$=>(-8)(0)+6y=42$ solve for $y$ .

$=>0+6y=42$

$=>6y=42$

$=>y=7$ The $y$ -intercept is at $(0,7)$

How do you find the yy-intercept of -8x + 6y = 42-8x + 6y = 42?