How do you find the #y#-intercept of #-8x + 6y = 42#?

1 Answer
Parabola
May 2, 2018

The #y# intercept is at #(0,7)#.

Explanation:

When you have a linear equation in the form #ax+bx=c#, just substitute #0# in the place of #x# to get the #y# intercept.

#=>(-8)(0)+6y=42# solve for #y#.

#=>0+6y=42#

#=>6y=42#

#=>y=7# The #y#-intercept is at #(0,7)#

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