A cylinder with radius 3 and height 4?

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Answer 1 · 2018-05-01T21:47:54

Volume $= 36 π$ $=36pi$
Lateral Surface Area $= 24 π$ $=24pi$
Total Surface Area $= 96 π$ $=96pi$

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Radius $r = 3$ $r=3$
Height $h = 4$ $h=4$

Volume of a Cylinder is $V = π r^{2} h$ $V = pir^2h$

$V = π 3^{2} (4)$ $V = pi3^2(4)$

$V = 36 π$ $V=36pi$

Lateral Surface Area is $L A = 2 π r h$ $LA = 2pirh$

$L A = 2 π (3) (4)$ $LA = 2pi(3)(4)$

$L A = 24 π$ $LA = 24pi$

Total Surface Area is $T A = 2 π r h + 2 π r^{2} h$ $TA= 2pirh + 2pir^2h$

$T A = 2 π (3) (4) + 2 π 3^{2} (4)$ $TA = 2pi(3)(4) + 2pi3^2(4)$

$T A = 24 π + 2 (36 π)$ $TA = 24pi +2(36pi)$

$T A = 24 π + 72 π$ $TA = 24pi +72pi$

$T A = 96 π$ $TA = 96pi$