How do you multiply #(2x - 5) ( 6x ^ { 2} - 6x - 11)#?

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Answer 1 · 2018-05-01T16:03:07

#12x^3-42x^2+8x+55#

Simply multiply each term in each bracket, but not terms in the same bracket.

#(color(red)(2x)color(blue)(-5))(color(green)(6x^2)color(red)(-6x)color(blue)(-11))#

#color(red)(2x) xx color(green)(6x^2)=color(orange)(12x^3)#

#color(red)(2x) xx color(red)(-6x)=color(green)(-12x^2)#

#color(red)(2x) xx color(blue)(-11)=color(red)(-22x)#

#color(blue)(-5) xx color(green)(6x^2)=color(green)(-30x^3)#

#color(blue)(-5) xx color(red)(-6x)=color(red)(30x)#

#color(blue)(-5) xx color(blue)(-11)=color(blue)(55)#

Collect like terms:

#color(orange)(12x^3)color(green)(-12x^2-30x^2)color(red)(-22x+30x)color(blue)(+55)#

#rArr color(orange)(12x^3)color(green)(-42x^2)color(red)(+8x)color(blue)(+55)#

#rArr 12x^3-42x^2+8x+55#