How do you solve # log 6x-3=-4#?

1 Answer
Daniel L.
May 1, 2018

See explanation.

Explanation:

#log6x-3=-4#

First step is yo move all numbers (here #-3#) to right side:

#log6x=-4+3#

#log6x=-1#

Now we have to change the number into a logarithm using the formula: #b=log_a a^b#

#log6x=log0.1#

Now we can change the #log# equation to the equation using only expressions under #log# sign:

#6x=0.1#

#x=1/10-:6#

#x=1/10*1/6#

Answer:

#x=1/60#

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