How do you solve #\frac { - 3a } { a + 6} = \frac { 3} { a - 6}#?

1 Answer
Manasvini Nittala
May 1, 2018

the value of #a# is #2 or 3#

Explanation:

given that #(-3a)/(a+6)=3/(a-6)rArr-3a(a-6)=3(a+6)#
#rArr-3a^2+18a=3a+18rArr-3a^2+18a-3a-18=0#
#rArr-3a^2+15a-18=0rArr3a^2-15a+18=0rArr#
#3a^2-6a-9a+18=0rArr3a(a-2)-9(a-2)=0rArr#
#(3a-9)(a-2)=0rArra=2 or3#

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