How many moles of NaOH are present in 26,5 mL of 0.190 M NaOH?

2 Answers
zhirou
Apr 28, 2018

#"0.00504 mol"#.

Explanation:

#"0.190 M"# #NaOH# means that, for every #1# liter of #NaOH#, there will be #0.190# moles:

#"0.190 mol"/"1L"#

So, using this ratio, we can find how many moles of #NaOH# there are in #"26.5 mL"#, or #"0.0265 L"#:

#"0.190 mol"/"1L" = "0.190 × 0.0265 mol"/"0.0265 L" = "0.00504 mol"/"0.0265 L"#

Michael
Apr 28, 2018

0.00504

Explanation:

Concentration = moles of solute / volume of solution.

#sf(c=n/v)#

#:.##sf(n=cxxv)#

#:.##sf(n_(NaOH)=0.0190xx26.5/1000=0.00504)#

2 points to note:

  1. I have converted ml to litre by dividing by 1000.

  2. I have rounded to 3 sig. figs since the volume is given to this significance.

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