How do you solve $6 - 4 x = 6 x - 8 x - 2$ $6- 4x = 6x - 8x - 2$ ?

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Answer 1 · 2018-04-28T11:56:39

$x = 4$ $x=4$

$6 - 4 x = 6 x - 8 x - 2$ $6-4x=6x-8x-2$

We need to collect terms in x on the left side of the equation and numeric values on the right side.

$- 4 x - 6 x + 8 x = - 2 - 6$ $-4x-6x+8x=-2-6$

$- 2 x = - 8$ $-2x=-8$

$x = 4$ $x=4$

How do you solve 6−4x=6x−8x−26- 4x = 6x - 8x - 2?