How do you factor #48y^2 - 72xy + 27x^2#?

1 Answer
Dibyajyoti D.
Apr 28, 2018

The answer is #3(3x-4y)^2#

Explanation:

In the given expression we can see that the coefficients of the polynomials are #48,72 # and #27# these numbers are divisible by #3#
When you take 3 common from these numbers this expression becomes:
#3(9x^2-24xy+16y^2)#
and when we factorise #9x^2-24xy+16y^2# we get #(3x-4y)^2#
so finally we get #3(3x-4y)^2# as our answer.

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