What is the square root of the difference between half a number and two thirds of a different number?

Question

1753 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-27T15:05:43

$\sqrt{(\frac{x}{2}) - (\frac{2 y}{3})}$ $sqrt((x/2)-((2y)/3))$

The way the question is phrased, we must first find the difference between the two terms before taking the square root.

Half of a number can be represented as a variable (in this case, $x$ $x$ ) divided by $2$ $2$ :

$\frac{x}{2}$ $x/2$

Two thirds of a different number can be represented as a different variable (in this case, $y$ $y$ ) multiplied by $2$ $2$ and divided by $3$ $3$ :

$2 \frac{y}{3}$ $2y/3$

Next, we subtract the second term from the first term to find the difference:

$\frac{x}{2}$ $x/2$ - $\frac{2 y}{3}$ $(2y)/3$

Now, all we have to do is put the whole expression under a radical symbol to get the square root:

$\sqrt{(\frac{x}{2}) - (\frac{2 y}{3})}$ $sqrt((x/2)-((2y)/3))$