#x+y=10" " and x-y=2#
What is #x?#
↳Redirected from
"What is the oxidation number of copper?"
#|(x+y=10),(x-y=2)|#
Add both equations together.
#x+x+y-y=10+2#
#2x=12|:2#
#x=6#
Sub the result into any of the two equations for #x#
#6+y=10|-6#
#y=4#
Given
#x+y=10#
#x-y= 2#
Solve for #x#
This is a Simultaneous Equations problem.
Add the equations to let #y# drop out as zero
#color(white)(m)##x+y=10#
#color(white)(m)##x-y= 2#
#color(white)()#―――――――
#2x color(lightgray) (+ 0) = 12#
#color(white)(n)##xcolor(white)(mnn)= 6# #larr# answer
If #x# equals #6#, then #y# must equal #4#
#color(white)(mmmmmm)#―――――――
Check
Sub in the values in the place of the letters to verify that the equations are still correct.
#color(white)(m)##x+y=10#
#color(white)(m)##6+4=10# ✓
#color(white)(m)##x-y=2#
#color(white)(m)##6-4=2# ✓
#Check#
