In the laboratory you are asked to make a 0.708 m ammonium chloride solution using 315 grams of water. How many grams of ammonium chloride should you add?

1 Answer
Mr. Mike
Apr 25, 2018

You need to add #11.9" grams "NH_4Cl# to #315" grams of water"# to make a #0.708 " M"# solution of ammonium chloride.

Explanation:

First, let's calculate the molecular weight of ammonium chloride, #M_w^(NH_4Cl)#. For this we'll need its molecular formula, #NH_4Cl#.

#M_w^(NH_4Cl)=14.0067+4(1.00794)+35.453=53.49146#

Now we can calculate the number of grams required remembering that the density of water is 1000 gm/liter.

#315cancel(" grams water")xx(1 cancel(" liter water"))/(1000 cancel(" grams water"))xx(0.708cancel(" moles "NH_4Cl))/cancel("liter water")xx(53.49146" grams "NH_4Cl)/(cancel("mole "NH_4Cl))~~11.9" grams "NH_4Cl#

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