How do you solve -2k ^ { 2} + 8= 0?

3 Answers
Apr 24, 2018

k=+2 or -2

Explanation:

-2k^2+8=0

-2k^2+8-8=0-8

-2k^2=-8

((-2k^2)/-2)=-8/-2

k^2=4

sqrt(k^2)= +-sqrt(4)

k=+-2

Apr 24, 2018

k=+-2

Explanation:

"subtract 8 from both sides of the equation"

rArr-2k^2=-8

"divide both sides by "-2

rArrk^2=4

color(blue)"take the square root of both sides"

rArrk=+-sqrt4larrcolor(blue)"note plus or minus"

rArrk=+-2

Apr 24, 2018

k=-2,2

Explanation:

Solve:

-2k^2+8=0

Subtract 8 from both sides.

-2k^2=-8

Divide both sides by -2.

k^2=(-8)/(-2)

k^2=8/2

k^2=4

Take the square root of both sides.

sqrt(k^2)=+-sqrt4

Apply rule sqrt(a^2)=a.

k=+-2