How do you solve $\frac{5}{d - 6} = \frac{4}{d + 1}$ $\frac { 5} { d - 6} = \frac { 4} { d + 1}$ ?

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Answer 1 · 2018-04-24T01:05:10

cross multiply!

$d = - 29$ $d=-29$

so you must cross multiply the equation (butterfly?)
(Basically multiply diagonally)
so multiply
$5 \cdot (d + 1) = 5 d + 5$ $5 *(d+1) = 5d+5$

$(d - 6) \cdot 4 = 4 d - 24$ $(d-6) * 4 = 4d-24$

so then

$4 d - 24 = 5 d + 5$ $4d-24=5d+5$
solve like normal!
$- 24 = d + 5$ $-24=d+5$

$- 29 = d$ $-29=d$

How do you solve 5d−6=4d+1\frac { 5} { d - 6} = \frac { 4} { d + 1}?