How do you solve $x^ { 2} ( x ^ { 2} - 49) - 64( x ^ { 2} - 49) = 0$ ?

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Answer 1 · 2018-04-24T00:51:52

so with this equation you can see that the factors are
$(x^2-49)$ and $(x^2-64)$

from there, set both factors equal to 0

$x^2-49=0$
add 49 to both sides
$x^2=49$
square root
$sqrtx=sqrt49$
$x=7$

same process for the other one, square root of 64 is 8, etc

so

$x={7,8}$

How do you solve x^ { 2} ( x ^ { 2} - 49) - 64( x ^ { 2} - 49) = 0x^ { 2} ( x ^ { 2} - 49) - 64( x ^ { 2} - 49) = 0?