How do you solve #x^ { 2} ( x ^ { 2} - 49) - 64( x ^ { 2} - 49) = 0#?

1 Answer
Joltii
Apr 24, 2018

so with this equation you can see that the factors are
#(x^2-49)# and #(x^2-64)#

from there, set both factors equal to 0

#x^2-49=0#
add 49 to both sides
#x^2=49#
square root
#sqrtx=sqrt49#
#x=7#

same process for the other one, square root of 64 is 8, etc

so

#x={7,8}#

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