How do you solve $x^{2} (x^{2} - 49) - 64 (x^{2} - 49) = 0$ $x^ { 2} ( x ^ { 2} - 49) - 64( x ^ { 2} - 49) = 0$ ?

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Answer 1 · 2018-04-24T00:51:52

so with this equation you can see that the factors are
$(x^{2} - 49)$ $(x^2-49)$ and $(x^{2} - 64)$ $(x^2-64)$

from there, set both factors equal to 0

$x^{2} - 49 = 0$ $x^2-49=0$
add 49 to both sides
$x^{2} = 49$ $x^2=49$
square root
$\sqrt{x} = \sqrt{49}$ $sqrtx=sqrt49$
$x = 7$ $x=7$

same process for the other one, square root of 64 is 8, etc

so

$x = {7, 8}$ $x={7,8}$

How do you solve x2(x2−49)−64(x2−49)=0x^ { 2} ( x ^ { 2} - 49) - 64( x ^ { 2} - 49) = 0?