The oxidation number of sulphur in sulphuric acid h2so4 is?

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Answer 1 · 2018-04-23T01:38:19

+6

O.N of Oxygen= -2
O.N of Hydrogen= +1
O.N of Sulphur= x(say)

Now,

#2(1)+x+4(-2)=0#
#x-6=0#
#x=6#

Thus, O.N. of Suplhur is 6

Answer 2 · 2018-04-23T12:44:41

#+6#

In #H_2SO_4#, hydrogen exists in its usual #+1# state, and oxygen exists in its #-2# state.

Let #x# be the oxidation number of sulfur in sulfuric acid. Then we got:

#1*2+x-2*4=0#

#2+x-8=0#

#x-6=0#

#x=6#

So, sulfur exists in the #+6# state.