How do you find the domain of #h(x)= 1/(x+1)#?

1 Answer
VNVDVI
Apr 22, 2018

All real numbers excluding #x=-1#; #(-oo, -1) U (-1,oo)#

Explanation:

The domain includes all values of #x# for which #h(x)# exists.

For rational functions (such as this one), the domain doesn't exist for values of #x# which cause division by #0.# So, let's determine which values of #x# cause the denominator to equal #0:#

#x+1=0#

#x=-1#.

Then, the domain is all values of #x# excluding #x=-1.# In interval notation,

#(-oo, -1) U (-1,oo)#

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