Based on the estimates log(2) = .03 and log(5) = .7, how do you use properties of logarithms to find approximate values for $log (80)$ $log(80)$ ?

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Based on the estimates log(2) = .03 and log(5) = .7, how do you use properties of logarithms to find approximate values for $log (80)$ $log(80)$ ?

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Answer 1 · 2018-04-22T14:35:54

0.82

Explanation:

we need to know the log property

$log a \cdot b = log a + log b$ $loga*b=loga+logb$

$log (80) = log (8 \cdot 10) = log (8 \cdot 5 \cdot 2) = log (4 \cdot 2 \cdot 5 \cdot 2) = log (2 \cdot 2 \cdot 2 \cdot 5 \cdot 2)$ $log(80)=log(8*10)=log(8*5*2)=log(4*2*5*2)=log(2*2*2*5*2)$

$log (2 \cdot 2 \cdot 2 \cdot 5 \cdot 2) = log 2 + log 2 + log 2 + log 5 + log 2 = 4 log 2 + log 5$ $log(2*2*2*5*2)=log2+log2+log2+log5+log2=4log2+log5$

$4 \cdot (0.03) + 0.7 = 0.12 + 0.7 = 0.82$ $4*(0.03)+0.7=0.12+0.7=0.82$

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Based on the estimates log(2) = .03 and log(5) = .7, how do you use properties of logarithms to find approximate values for $log (80)$ $log(80)$ ?

1 Answer

Explanation:

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Based on the estimates log(2) = .03 and log(5) = .7, how do you use properties of logarithms to find approximate values for log(80)log(80)?

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Explanation:

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Based on the estimates log(2) = .03 and log(5) = .7, how do you use properties of logarithms to find approximate values for $log (80)$ $log(80)$ ?