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How do you simplify #(a^ -6) * (b^ 2) / (a^ -3) * (b^8)#?

1 Answer

sushi · Kalit Gautam

Apr 22, 2018

#a^(-3).b^10#

Explanation:

#1/a^-3 = a^((-3).(-1)) = a^3#

So ;

#a^(-6)*(b^2)/a^(-3)*b^8 =a^(-6)*b^2.a^3*b^8#

= #a^((-6+3)).b^((2+8))#

= #a^(-3).b^10#

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