How do you simplify #(9y^2+3y)/(6y^2)#?

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Answer 1 · 2018-04-21T13:34:02

#(3y+1)/(2y)#

#(9y^2+3y)/(6y^2)=(3y(3y+1))/(6y^2)#

#(cancel(3y)(3y+1))/(cancel(6y^2)2y) = (3y+1)/(2y)#

Answer 2 · 2018-04-21T13:40:35

#color(maroon)(=> 3/2 + 1/(2y))#

#(9y^2 + 3y) / (6y^2)#

#=> (9y^2) / (6y^2) + 3y / (6y^2)#

#=> (9 * cancel(y^2)) / (6 * cancel(y^2)) + (3 * cancel y) / (6 * cancel(y^2)^color(red)(y)#

#=> cancel9^color(green)3 / cancel 6 ^ color(green)(2) + cancel (3)^color(blue)(1) / cancel (6)^color(blue)(2y)#

#=> 3/2 + 1/(2y)#