How do you solve the system of equations $-8x + 12y = 4$ and $- 10x - 2y = 22$ ?

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How do you solve the system of equations $-8x + 12y = 4$ and $- 10x - 2y = 22$ ?

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Answer 1 · 2018-04-21T00:26:50

You need to use simultaneous equations.

Explanation:

I prefer substitution but other ways will work. Take one of the equations and solve for either x or y. Then substitute the value for x or y into the second equation.

e.g.
$x-2y=7$ and $2x+7y = -8$

$x-2y=7$ Solve for x
$x=7+2y$ Sub this into equation 2

$2(7+2y)+7y = -8$ Solve for y
$14+4y+7y = -8$
$11y=-22$
$y=-2$

From above
$x = 7 +2y$ (we now know y = -2)
$x = 7+2(-2)$
$x = 3$

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How do you solve the system of equations $-8x + 12y = 4$ and $- 10x - 2y = 22$ ?

1 Answer

Explanation:

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Science

Math

Humanities

... and beyond

How do you solve the system of equations -8x + 12y = 4-8x + 12y = 4 and - 10x - 2y = 22- 10x - 2y = 22?

1 Answer

Explanation:

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How do you solve the system of equations $-8x + 12y = 4$ and $- 10x - 2y = 22$ ?