For a doublet of doublet, how many neighbors does it have?

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For a doublet of doublet, how many neighbors does it have?

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Answer 1 · 2018-04-20T22:27:54

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Explanation:

For a doublet of doublet you would see 4 peaks. When drawing the splitting tree this becomes obvious. So a splitting tree of a doublet of doublet would look like the following:
![https://useruploads.socratic.org/tYJUvD7zT0uS1ZGM18ww_doublet_of_doublet.jpg)
Here the proton what we look at in the molecule is the upper line. This proton has two neighbors with different coupling constants $(J)$ $(J)$ .

So we start with the proton who has the highest $J$ $J$ , which follows the $n + 1$ $n+1$ rule. Meaning we would see two peaks, shown between the arrow $J_{b a}$ $J_(ba)$ .

Now we take the proton with the lower $J$ $J$ , which from each peak will make two doublets shown as $J_{b c}$ $J_(bc)$ .

This gives a signal with a doublet of doublets. Since we use $n + 1$ $n+1$ rule twice the amount of neighbors is 2.

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For a doublet of doublet, how many neighbors does it have?

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