How do you evaluate #a(b^x)# given a=-3, b=5, x=2?

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Answer 1 · 2018-04-18T21:30:49

#-75#

#a(b^x)# is the same as #a * b^x#.

here, #a = -3#

#b = 5# and #x = 2#, so #b^x = 5^2#

#5^2 = 25#

#-3 * 5^2 = -3 * 25#

#= -75#