How do you solve $(x - 9) ^ { 2} - 4= 0$ ?

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Answer 1 · 2018-04-17T01:26:49

$x=11,7$

$(x-9)^2 -4 =0$
$(x-9)^2 = 4$
$(x-9) = +-sqrt 4$
$x-9 = +-2$
$x=11, 7$
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How do you solve (x - 9) ^ { 2} - 4= 0(x - 9) ^ { 2} - 4= 0?