How do you add or subtract 5/(4x^2y) – y/(14xz)?

1 Answer
Elias
Apr 17, 2018

We begin by trying to find a common denominator for these two fractions....
1) The two denominators that we are working with are 4x^2y and 14xz
2) To find the LCD we must factor out the two numbers
14xz = 2 *7 *x*z
4x^2y=2^2*x^2*y
3) Then we find the product of each factor with the highest power
(2^2)(x^2)(7)(y)(z) = 28x^2yz

Then we try to set each denominator to the LCD that we found (28x^2yz)/(28x^2yz) 28x^2yz)/(28x^2yz)
4) (5)/(4x^2y)*(7z)/(7z) = (35z)/(28x^2yz)

y/(14xz) * (2xy)/(2xy) = (2xy^2)/(28x^2yz)

Now since we have a common denominator, we can now simply the equation into one fraction
(35z-2xy^2)/(28x^2yz)
That took forever to write out on this,,,

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