Which is the morality of Y when 180 g of Y is dissolved in enough water to make a 3 L solution? (Y =30 g)

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Which is the morality of Y when 180 g of Y is dissolved in enough water to make a 3 L solution? (Y =30 g)

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Answer 1 · 2018-04-15T05:59:36

Molarity of the solution = $2 M$ $2M$ .

Explanation:

as, Y is the solute
so, $M o l a r i t y (M) = \frac{n_{s o l u t e}}{Volume of solution (in L)}$ $Molarity(M)=n_(solute)/"Volume of solution (in L)"$
where, $n_{s o l u t e} =$ $n_(solute)=$ no. of moles of solute
now, $M = \frac{\frac{W (G i v e n M a s s)}{M (M o l a r M a s s)}}{V o l u m e o f s o l u t i o n (L)}$ $M=[(W(Given Mass))/(M(Molar Mass))]/(Volume of solution ( L))$
$M = \frac{\frac{180}{30}}{3}$ $M=(180/30)/3$
$M = \frac{6}{3} = 2 M$ $M=6/3=2M$

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Which is the morality of Y when 180 g of Y is dissolved in enough water to make a 3 L solution? (Y =30 g)

1 Answer

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