Titration Problem - Calculate the concentration of 20.0 mL of an H2SO4 solution that requires 27.7 mL of a 0.100 M NaOH solution?

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Apr 14, 2018

#0.06925M#

Explanation:

#2NaOH+H_2SO_4#--->#Na_2SO_4+2H_2O#

First calculate the number of moles (or amount) of the known solution, which in this case is the NaOH solution.
The volume of NaOH is #27.7 mL#, or #0.0277L#.
The concentration of NaOH is #0.100M#, or in other words, #0.100# mol/L

Amount = concentration x volume

#0.0277Lxx0.100M=0.00277# #mol#

As you can see from the reaction equation, the amount of #H2_SO_4# is half the amount of #NaOH#, as there is #2NaOH# but only #1H_2SO_4#

Amount of #H_2SO_4=0.00277/2=0.001385# #mol#

Concentration = amount/volume

#0.001385# #mol#/#0.02L=0.06925M#

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