Calculate the value of the change of H ?

Question

Calculate the value of the change of H ?

N2 + O2 -> N2O5

H2 + 1/2 O2 -> H2O Change of H = -285.8 kj/mol
N2O5 + H2O -> 2HNO3 Change of H = -76.6 kj/mol
1/2N2 + 3/2O2 + 1/2H2 -> HNO3 Change of H = -174.1kj/mol

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Answer 1 · 2018-04-13T05:45:25

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Explanation:

First of all, the final reaction required is

$N_{2} + \frac{5}{2} O_{2} \to N_{2} O_{5} ..........(4)$ $" "N_2 + 5/2O_2->N_2O_5" ..........(4)"$ .

If we number the 3 reactions serially as $(1), (2), (3),$ $(1),(2),(3),$ then $(4)$ $(4)$ can be obtained as $2 \times (3) - (1) - (2)$ $2xx(3)-(1)-(2)$

Just plug in the values for the reactions, and you will get the value of $DeltaH$ of reaction $(4)$ .

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Calculate the value of the change of H ?

N2 + O2 -> N2O5

H2 + 1/2 O2 -> H2O Change of H = -285.8 kj/mol
N2O5 + H2O -> 2HNO3 Change of H = -76.6 kj/mol
1/2N2 + 3/2O2 + 1/2H2 -> HNO3 Change of H = -174.1kj/mol

1 Answer

Explanation:

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Impact of this question

Science

Math

Humanities

... and beyond

Calculate the value of the change of H ?

N2 + O2 -> N2O5 H2 + 1/2 O2 -> H2O Change of H = -285.8 kj/mol N2O5 + H2O -> 2HNO3 Change of H = -76.6 kj/mol 1/2N2 + 3/2O2 + 1/2H2 -> HNO3 Change of H = -174.1kj/mol

1 Answer

Explanation:

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N2 + O2 -> N2O5

H2 + 1/2 O2 -> H2O Change of H = -285.8 kj/mol
N2O5 + H2O -> 2HNO3 Change of H = -76.6 kj/mol
1/2N2 + 3/2O2 + 1/2H2 -> HNO3 Change of H = -174.1kj/mol