How do you complete the equation $C_{8} H_{18} \to C_{6} H_{14} +_{_}$ $C_8H_18 -> C_6H_14 + __$ ?

Question

How do you complete the equation $C_{8} H_{18} \to C_{6} H_{14} +_{_}$ $C_8H_18 -> C_6H_14 + __$ ?

2 Answers

Impact of this question

2138 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-12T17:29:22

$C_{2} H_{4}$ $"C"_2"H"_4$

Explanation:

$C_{8} H_{18} \to C_{6} H_{14} +__$ $"C"_8"H"_18 -> "C"_6"H"_14 + "__"$

There are $8$ $8$ carbons & $18$ $18$ Hydrogens in reactant side and $6$ $6$ carbons & $14$ $14$ Hydrogens in product side. So, another molecule should contain $2$ $2$ carbons and $4$ $4$ Hydrogens.

$"C"_8"H"_18 -> "C"_6"H"_14 + underbrace("C"_2"H"_4)$
$color(white)(............................)"ethene"$

Answer 2 · 2018-04-12T17:31:44

it is the example of Aromatization in which higher alkanes is divided into smaller akanes & alkenes.
so, eqn is,
$C_8H_18 rarr C_6H_14 + C_2H_4$
octane $rarr$ hexane + ethene

Science

Math

Humanities

... and beyond

How do you complete the equation $C_{8} H_{18} \to C_{6} H_{14} +_{_}$ $C_8H_18 -> C_6H_14 + __$ ?

2 Answers

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you complete the equation C_8H_18 -> C_6H_14 + __C8H18→C6H14+_C_8H_18 -> C_6H_14 + __?

2 Answers

Explanation:

Related questions

Impact of this question

How do you complete the equation $C_{8} H_{18} \to C_{6} H_{14} +_{_}$ $C_8H_18 -> C_6H_14 + __$ ?