What is the perimeter of a triangle with corners at (2 ,5 ), (9 ,2 ), and (3 ,8 )?

1 Answer
Apr 12, 2018

sqrt(58) + sqrt(72) + sqrt(10)

Explanation:

This requires you to apply the distance formula three times. Recall that the distance between two points (x_1, y_1) and (x_2, y_2) is D = sqrt( (x_2 - x_1)^2 + (y_2 - y_1)^2 ).

The distance between (2, 5) and (9, 2) is D_1 = sqrt( (9 - 2)^2 + (2 - 5)^2 ) = sqrt( 49 + 9) = sqrt(58).

The distance between (9, 2) and (3, 8) is D_2 = sqrt( (3-9)^2 + (8-2)^2 ) = sqrt(36 + 36) = sqrt(72).

The distance between (3, 8) and (2, 5) is D_3 = sqrt( (2 - 3)^2 + (5 - 8)^2 ) = sqrt(1 + 9) = sqrt(10).

The perimeter is thus P = D_1 + D_2 + D_3 = sqrt(58) + sqrt(72) + sqrt(10).