A system of equations contains the lines x+4y=2 and x−2y=c. When solving the system algebraically, it is determined that x=6. What is the value of c in the second equation?
1 Answer
Apr 12, 2018
c=8
Explanation:
- To solve this problem you must begin by substituting 6 for x.
6+4y=2 and 6-2y=c - Solve each for y.
y=#1/2# -#3/2# and y=#-c/2# + 3 - Set the equations equal to each other.
#1/2# -#3/2# =#-c/2# + 3 - Multiply everything by 2 to cancel out the denominators.
1-3=-c+6 - Simplify
-2=-c+6 - Solve for c by subtracting 6 and dividing by -1.
c=8
