How do you solve #\frac { 1} { 3} ( 21- 3x ) = \frac { 1} { 2} ( 8- 4x )#?

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Answer 1 · 2018-04-10T15:48:42

#x=-3#

Here is the math that I did, in steps. To get rid of the fractions I multiplied the sides by their reciprocal's.

#1/3 (21-3x)=1/2(8-4x)#

#2(21-3x)=3(8-4x)#

#42-6x=24-12x#

#42=24-6x#

#18=-6x#

#-3=x#

#x=-3#