What is the slope of the line perpendicular to the line represented by the equation #2x+4y=12#?

1 Answer
Divya Prakash S. · Tony B
Apr 10, 2018

The slope of the line perpendicular to the line #2x+4y=12# is 2.

Explanation:

#2x + 4y=12#
#=>y= (12 - 2x)/4#
#=>y= 3 - x/2#
#=>y= -x/2 + 3#
This is in the form of #y=mx+b# where m is the slope.
There the slope of the above line is #-1/2#.
Since, the slope of line perpendicular to a given line is the negative reciprocal of it.
Therefore, the slope of the required perpendicular line
#= -1/(-1/2)#
#=-(-2)#
#=2#

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