A cylinder of volume 1m3 is filled with 1kg of CO and 100g of H2O. What is the molar percentage of CO in the mixture in the cylinder?

1 Answer
Andrea B.
Apr 10, 2018

87%

Explanation:

in 1 kg of CO you have #n= g/(MM)=(1000g)/(28g/(mol))=35,7 mol#
in 100 g of #H_2O# you have #n= g/(MM)=(100g)/(18g/(mol))=5,5 mol#
total mol = 35,7 + 5,5 = 41,2 mol
Molar percentage of CO =#(mol CO)/(mol_(t)) xx 100 =35.7/41.2=87%#

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