How do you solve $6 = \frac{20}{x - 2}$ $6 = 20/(x-2)$ ?

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Answer 1 · 2018-04-10T02:33:16

$x = \frac{16}{3}$ $x=16/3$

$6 = \frac{20}{x - 2}$ $6=20/(x−2)$

Multiply both sides by $x - 2$ $x-2$ . This will cancel $x - 2$ $x-2$ on the right-hand side.

$6 (x - 2) = 20$ $6(x-2)=20$

Expand the left-hand side.

$6 x - 12 = 20$ $6x-12=20$

Add $12$ $12$ to both sides.

$6 x = 32$ $6x=32$

Divide both sides by $6$ $6$ .

$x = \frac{32}{6}$ $x=32/6$

Simplify by dividing the numerator and denominator by $2$ $2$ .

$x = \frac{16}{3}$ $x=16/3$

How do you solve 6=20x−26 = 20/(x-2)?