What is the [H3O+] for a solution with a pH of 7.52?

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Answer 1 · 2018-04-09T11:35:42

#10^(-7.52) M#.

We know that the concentration of #H_3O^+# ions will be the same as the concentration of #H^+# ions.

We also know that #pH = -log[H^+]#.
So, we can solve for #[H^+]# (or #[H_3O^+]#) by plugging in the known #pH# value:

#pH = -log[H^+]#
#7.52 = -log[H^+]#
#-7.52 = log[H^+]#
#10^(-7.52) = [H^+]#

Answer 2 · 2018-04-09T13:32:56

#10^-7.52 \ "M"#

The #"pH"# of a substance is given through the following equations:

#"pH"=-log[H^+]# or #"pH"=-log[H_3O^+]#

#[H^+]# or #[H_3O^+]# are the concentrations of hydrogen ions or hydronium ions in terms of molarity.

Note that they can be used interchangeably, since #H^+# will react with water to form #H_3O^+#.

So, we got:

#-log[H_3O^+]=7.52#

#:.[H_3O^+]=10^-7.52 \ "M"#