Make #a# the subject ? #I=(M(a^2 + b^2))/12#

Question

I=M((a^2 + b^2)/12

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Answer 1 · 2018-04-09T11:00:13

Please look below.

#I = (M(a^2+b^2))/12#

#(12I)/M = a^2 + b^2#

#a^2 = (12I)/M - b^2#

#a = +-sqrt((12I)/M - b^2)#