How can you simplify $\frac{125 a^{15} b^{7}}{- 8 a^{3} b^{4}}$ $(125a^15b^7)/(-8a^3b^4)$ ?

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How can you simplify $\frac{125 a^{15} b^{7}}{- 8 a^{3} b^{4}}$ $(125a^15b^7)/(-8a^3b^4)$ ?

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Answer 1 · 2018-04-09T00:08:44

$- \frac{125 a^{12} b^{3}}{8}$ $-(125a^12b^3)/(8)$

Explanation:

$\frac{125}{- 8}$ $125/-8$ cannot be simplified, it is in the simplest form a fraction can be in

Dividing exponents with the same base: $\frac{a^{b}}{a^{c}} = a^{b - c}$ $a^b/a^c=a^(b-c)$

Apply that in this expression:

$\frac{125}{- 8} \cdot \frac{a^{15 - 3}}{1} \cdot \frac{b^{7 - 4}}{1}$ $125/-8*a^(15-3)/1*b^(7-4)/1$

$\frac{125}{- 8} \cdot \frac{a^{12}}{1} \cdot \frac{b^{3}}{1}$ $125/-8*a^12/1*b^3/1$

$- \frac{125 a^{12} b^{3}}{8}$ $-(125a^12b^3)/(8)$

Answer 2 · 2018-04-09T00:59:01

To simplify this expression, the following exponential rule is needed:
$\frac{a^{b}}{a^{c}} = a^{b - c}$ $(a^b)/(a^c) = a^(b-c)$

$\frac{125 a^{15} b^{7}}{- 8 a^{3} b^{4}}$ $(125a^15b^7)/(-8a^3b^4)$
$= - \frac{125 a^{15 - 3} b^{7 - 4}}{8}$ $=-(125a^(15-3)b^(7-4))/8$
$= - \frac{125 a^{12} b^{3}}{8}$ $=-(125a^12b^3)/8$

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How can you simplify $\frac{125 a^{15} b^{7}}{- 8 a^{3} b^{4}}$ $(125a^15b^7)/(-8a^3b^4)$ ?

2 Answers

Explanation:

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